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-x^2+29x+342=0
We add all the numbers together, and all the variables
-1x^2+29x+342=0
a = -1; b = 29; c = +342;
Δ = b2-4ac
Δ = 292-4·(-1)·342
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-47}{2*-1}=\frac{-76}{-2} =+38 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+47}{2*-1}=\frac{18}{-2} =-9 $
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